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Re: Dr. Dobbs Dev. Update 1/5 July 94 & Schneier
Excerpts from internet.cypherpunks: 3-Jul-94 Re: Dr. Dobbs Dev. Update
1.. by Eli [email protected]
> int byte_ones(int a)
> // hope this is correct...
> {
> a = (a & 0x55) + (a & 0xAA)/2; // 0x55 == 01010101b
> a = (a & 0x33) + (a & 0xCC)/4; // 0x33 == 00110011b
> a = (a & 0x0F) + (a & 0xF0)/16; // 0x0F == 00001111b
e> return a;
> }
Note that some compilers might not be smart enough to use logical shift
ops and instead use expensive division ops. Just to be safe...
int byte_ones(int a)
{
a = (a & 0x55) + ((a & 0xAA) << 1); // 0x55 == 01010101b
a = (a & 0x33) + ((a & 0xCC) << 2); // 0x33 == 00110011b
a = (a & 0x0F) + ((a & 0xF0) << 4); // 0x0F == 00001111b
return a;
}
And this runs in O(lg n) where n is the number of bits in `a'. Does
anybody have an algorithm for this that beats O(lg n)?
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Tim Nali \ "We are the music makers, and we are the dreamers of
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