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Re: Diffie-Hellman in GF(2^n)?
In article <[email protected]> you write:
> Most Diffie-Hellman implementations currently use the multiplicative group
> of prime fields. However, the multiplicative group of finite fields of
> characteristic 2 (GF(2^n)) can also be used and should be easier to
> implement. Is there any reason why they should not be used? Does anyone
> know the asymptotic running time of the best algorithm for calculating
> discrete logarithms in GF(2^n)?
I remember that the discrete log problem is quite a bit easier
in GF(2^n), but I don't remember how much easier. Let me try
to look it up...
A. Odlyzko has a paper recommending that people should not use
GF(2^n) for discrete log applications; in it he states that you
will need at the minimum n > 800, and probably n > 1500. (And
you also need to choose n carefully.) A quote from the abstract:
``Hence the fields GF(2^n) out to be avoided in all cryptographic
I don't know enough about number theory to judge for myself;
but you can read the (long) paper yourself at
I hope this helps!