Though this is starting to get tedious, I'll do my pedantic part and point out that O(log_2(n)) == O(log_k(n) * C) == O(log_k(n)); the log base doesn't matter in Big O Land. -- | GOOD TIME FOR MOVIE - GOING ||| Mike McNally <[email protected]> | | TAKE TWA TO CAIRO. ||| Tivoli Systems, Austin, TX: | | (actual fortune cookie) ||| "Like A Little Bit of Semi-Heaven" |