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Re: transaction costs in anonymous markets

On Mon, 16 Oct 1995, Sandy Sandfort wrote:

> This is only true if you assume everyone will do their own
> reputation evaluation.  This is a third-party insurer problem,
> really.  Either a "Lloyds of London" or a "Good Housekeeping" 
> model would do the trick.

Actually, this sounds a lot closer to someone like S&P or some other 
rating agency.


(defun modexpt (x y n)  "computes (x^y) mod n"
  (cond ((= y 0) 1)   ((= y 1) (mod x n))
	((evenp y) (mod (expt (modexpt x (/ y 2) n) 2) n))
	(t (mod (* x (modexpt x (1- y) n)) n))))